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The cross-section of a water trough is an equilateral triangle with a horizontal top edge. If the trough is 5m long and 25 com deep and water is flowing in at a rate of 0.25m^3, how fast is the water level rising when the water is 10cm deep at the deepest point
3 Answers
- gareLv 51 decade agoFavorite Answer
What is the width? We can calculate the area with your information, but not the volume. The rate of rise will decrease as it fills due to the increase of area, the formula needs to be shown on your homework page when it is turned in. The resulting formula is linear and the resulting point is defineable with a little more info.
- 1 decade ago
Volume of the tank=area of cross section*height
V=( /4)*5^2*h
Diff wrt time, t
dV/dt=( /4)*5^2*dh/dt
dV/dt=0.25
put above & solve for
dh/dt
