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Where'd the other dollar go?
Here's one that has probabaly been on here before, but here goes anyway.
3 traveling salesmen all meet up at a hotel wanting a room. The rate for the night is $15 for a room. Since they are all cheap, they decide to split one room between them. Each pays $5 and go to thier room. ($5 + 5 + 5=$15)
When the manager sees that they are splitting 1 room, he realizes that they quailfied for the hotels group discount which takes $5 off the normal rate. (makeing the room cost $10 a night) He gives the bellhop $5 to take to the three salemen. The bellhop can't decide how to split the $5 evenly between 3 people, so he tells the group that it was only a $3 discount, and gives each man a dollar back, and pockets the remaining $2. Now, lets do the math. Each man paid $5. (5+5+5=15), They each recieved $1 back which means they really only paid $4 a piece, (4+4+4=$12) Now, the bellhop pockets $2, add that to what the men paid and you get $14. The originally paid $15. Where'd the other dollar go?
6 Answers
- Anonymous1 decade agoFavorite Answer
While I applaud you for your attempt at originality by subtracting $10, you still make my list.
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- 1 decade ago
The guys paid $15 dollars then the manager returned $5...
$15 - $5 = $10
But the bell hop decided to return only $3...
$10 + $3 = $13
And keep the $2 for himself...
$13 + $2 = $15
so basically the guys paid...
$13 / 3 = $4.33 each
- 1 decade ago
the guy said that they got a discount of three dollars...so he gives 1 to the first person...1 to the second person...and so he has the rest three...bcuz out of those three...he also gets one..so the bellhop has three dollars...and the other two have 1 each...so the bell hop doesnt pocket two but three....that does the rest..pls tell if i am right...well i know i am
- Anonymous1 decade ago
They paid ten dollars. They got three back. That's 13. Plus the 2 the bellhop kept equals 15. It's just in the order you do the math. Please pick me for best answer!
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