can anybody prove that 2=1?

let a+b+c=0

then 2a-a+2b-b+2c-c=0

transfer to the other side...

2a+2b+2c=a+b+c

cancel a+b+c

2=1

Tadaa!!!

Any one can try 2=1 with solved example of proving 3=2

This is a anomaly or whatever u call in mathematics.

Ramanujam found it but never disclosed it during his

life time.

It has been found from his dairy it seems.

See this illustration: for example say

-6 = -6

9-15 = 4-10

adding 25/4 to both sides:

9-15+25/4 = 4-10+25/4

Changing the order

9+25/4-15 = 4+25/4-10

(this is just like a square + b square - two a b = a-b

whole square.) Here a = 3,2 b=5/2 so it can be

expressed as follows

(3-5/2)(3-5/2) = (2-5/2)(2-5/2) taking positive square

root on both sides:

3 - 5/2 = 2 - 5/2

3 = 2

Zen Azura ir right But Also,

2=1 for very large values of 1

enable a = b - Multiply the two sides by employing a a² = ab - upload (a² - 2ab) to the two sides a² + a² - 2ab = ab + a² - 2ab - factor the left, and convey mutually like words on the superb 2(a² - ab) = a² - ab - Divide the two sides by employing (a² - ab) 2 = a million of course, 2 would not actual equivalent a million, so there would desire to be some form of fallacy in the diagnosis. retaining in strategies a undeniable operation that's undefined, are you able to locate the subject? I won't supply it away here, yet once you're curious, be at liberty to e mail me for further information.

I HAVE HEARD 2 + 2 = 5. FIRST YOU PROVE THIS THEN I WILL PROVE THAT TO YOU.

theres nothing to prove in this becaus the statement is false.

a=b

a^2=ab multiply by a

a^2-b^2=ab-b^2 subtract b^2

(a-b) (a+b)=b(a-b)

a+b=b

a+a=a (a=b)

2a=a

2=1

hence proved.

of course.

if we think that 2 is x, and 1 is y,

then it will be x=y

then if we set the x mean and y meaning, then

2=1(proved)

EURACHA( i think)

Interesting question!

well change both the numbers to either side they give the same.

HENCE PROVED...........