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Differentiate calculus?
Differentiate calculus
Find expressions for dy/dx when i) y = 2t^2 ii) y = (1+2u)^4
I would really appreciate some help on these. I have no idea where to start.
2 Answers
- 1 decade agoFavorite Answer
`but ther is no x!!!!!!!
i) y = 2t^2
y' = 4t
ii) y = (1+2u)^4
y'= 4(1+2u)^3 2 = 8 (1+2u)^3
- Professor MaddieLv 41 decade ago
i) dy/dx=2 (2t) dt/dx
Take the derivative according to t like you normally would using power rule and then multiply by dt/dx because by the chain rule:
dy/dx=dy/dt * dt/dx
ii) dy/dx=4 (1+2u)^3 * 2 du/dx
Take the derivative according to general power rule and again
dy/dx=dy/du * du/dx
