Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

i NEED CONSECUTIVE INTEGERS HELP!?

If two consecutive integers such that 4 times the larger exceeds 3 times the smaller by 23.

Please show me algebreically and please show me how to do it!

7 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    Consecutive means one is x and one is x+1. That's all you need to know to do these.

    4 times the larger

    4(x + 1)

    exceeds 3 times the smaller

    3x

    by 23

    4(x+1) = 3x + 23

    4x + 4 = 3x + 23

    x = 19

    x + 1 = 20

  • 1 decade ago

    well, since they're consecutive, the two numbers can be x and x+1.

    then according to your thing, 4(x+1) = 3x + 23

    4x + 4 = 3x + 23

    x = 19

    so the smaller number is 19, and the larger is 20.

  • 1 decade ago

    translate to math language! let x be larger

    4x = 3y + 23 but y is 1 less than x (they're consecutive)

    so

    4x = 3(x-1) + 23

    4x = 3x -3 + 23

    4x - 3x = 20

    x = 20, so the other number is 19

  • 1 decade ago

    let first integer = x

    let second = x + 1

    4(x+1) = 3x + 23

    4x + 4 = 3x + 23

    x = 19

    19, 20

  • How do you think about the answers? You can sign in to vote the answer.
  • Anonymous
    1 decade ago

    4(x+1)=23+3x

    x=smaller int

    x+1=next consecutive (larger)

    4x+4=23+3x

    x+4=23

    x=19

  • S. B.
    Lv 6
    1 decade ago

    x & (x+1) represent two consecutive integers.

    4(x+1) = 3x + 23

    Give x & (x+1) as answers.

  • 1 decade ago

    (x+1)+x

    4x+4=3x+23

    x=19

Still have questions? Get your answers by asking now.