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i NEED CONSECUTIVE INTEGERS HELP!?
If two consecutive integers such that 4 times the larger exceeds 3 times the smaller by 23.
Please show me algebreically and please show me how to do it!
7 Answers
- Jim BurnellLv 61 decade agoFavorite Answer
Consecutive means one is x and one is x+1. That's all you need to know to do these.
4 times the larger
4(x + 1)
exceeds 3 times the smaller
3x
by 23
4(x+1) = 3x + 23
4x + 4 = 3x + 23
x = 19
x + 1 = 20
- car of boatLv 41 decade ago
well, since they're consecutive, the two numbers can be x and x+1.
then according to your thing, 4(x+1) = 3x + 23
4x + 4 = 3x + 23
x = 19
so the smaller number is 19, and the larger is 20.
- 1 decade ago
translate to math language! let x be larger
4x = 3y + 23 but y is 1 less than x (they're consecutive)
so
4x = 3(x-1) + 23
4x = 3x -3 + 23
4x - 3x = 20
x = 20, so the other number is 19
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- Anonymous1 decade ago
4(x+1)=23+3x
x=smaller int
x+1=next consecutive (larger)
4x+4=23+3x
x+4=23
x=19
- S. B.Lv 61 decade ago
x & (x+1) represent two consecutive integers.
4(x+1) = 3x + 23
Give x & (x+1) as answers.