what is the why intercept is the slope of the line is 2/3 and the line intercepts the x axis at 18?

y = mx + b is the slope-intercept form of a line, where m = slope and b = the y-intercept.

we have one point defined as (18,0) or x = 18, y = 0 (where the line crosses the x-axis). And we know the slop, 2/3, which is m.

So...

y = 2/3x + b

We want to solve for b (the y-intercept) so put our point in:

0 = 2/3(18) + b

0 = 12 + b

b = -12

There you have it! Hope this helps! :)

y = mx + b is the slope-intercept form of a line, where m = slope and b = the y-intercept.

we have one point defined as (18,0) or x = 18, y = 0 (where the line crosses the x-axis). And we know the slop, 2/3, which is m.

So...

y = 2/3x + b

We want to solve for b (the y-intercept) so put our point in:

0 = 2/3(18) + b

0 = 12 + b

b = -12

There you have it! Hope this helps! :)

y = mx + b

y=2x/3 + b

When y = 0, x = 18 --> (18,0) is x -intercept

Thus 0 = 2(18)/3 +b

b= -12 which is the y-intercept.

graph it and see make a point at x=18 y=0 and move two points up and three over until you hit the y axis