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Math problem from a test today...?

I am completely stumped on this question. It's from a test I already did, so this is for curiosity, not for someone else to do my homework.

If a company is building 478 houses and stand to profit $15,000 from a 2 bedroom model and $16,000 from a three bedroom model, and they are seeking to make exactly $5,713,000 in profit, how many of each house do they need to make?

Could someone show me how to solve this. I don't even care if you give me an answer, just let me know how to do it myself.... The answer must be numbers, not formulas. I just don't get how to solve it.

5 Answers

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  • 1 decade ago
    Favorite Answer

    It's a system of equations.

    Let x be the number of 2bedroom houses. Than 478 -x is the number of 3-bedroom houses.

    x(15,000) + (478 - x) (16,000) = 5713000

    15000x + (478)(16000) - 16000x = 5713000

    -1000x = 5713000 - (478)(16000)

    x = 5713000 - (478)(16000) / -1000

    so that's the number of 2b houses, then subtract from 478 for the number of 3b houses

  • 1 decade ago

    First of all, this problem is impossible as it is written. If they are building 478 houses, and making either 15,000 or 16000 profit from each, the least amount of profit they could make would be over 7 million (15000*478). I think you have the total profit wrong.

    Anyway,

    These types of problems are called systems of equations. You will have 2 variables, in this case 2 bedroom houses and 3 bedroom houses, and will be given enough information to make two equations.

    we'll let x=2 bedroom houses and y = 3 bedroom houses

    you know that the company will build 478 total houses, so x+y=478

    and you know that they want to make a total profit of 5,713,000 from the sale of the houses.

    since they make 15,000 profit for every 2 bedroom house, and 16,000 from every 3 bedroom house,

    the total profit can be written as

    15,000x + 16,000y = 5,713,000

    now that you have 2 equations, you can solve

    x+y=478

    15,000x+16,000y=5,713,000

    from the first equation, you can get that y=478-x

    now take that and substitute it into the second equation, so that you only have 1 variable to solve for

    15000x + 16000(478-x) = 5713000

    15000x + 7648000 - 16000x = 5713000

    -1000x = -1935000

    x=1935

    plug that back into the first equation to find the value of y

    x+y=478

    1935+y=478

    y=-1457

    So you can see why your numbers are wrong, but if they were right, this is how you work systems of equations.

  • 1 decade ago

    let X = number of 2 bedroom houses

    let Y = no. 3 bedroom houses

    X + Y = 478

    15000X + 16000Y = 5713000

    Solving these equations by elimination method will give you a negative number for Y. Which is not possible. The number of houses can't be negative. This problem is stated incorrectly.

  • Mitch
    Lv 7
    1 decade ago

    You've made a mistake somewhere in your numbers.

    If we take $5,713,000 / 478 houses, then the price of each house would be $11,951.88, which is MUCH LESS than the SELLING price of $15,000 and $16,000 respectively.

    Could the profit from the houses be $1,500 and $1,600 instead?

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  • 1 decade ago

    yea set this up as a system of equations problem... seems like the easiest choice to me. remember both substitution as well as addition elimination when doing these.

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