how much power will be dessipated by a 12 ohm resistor if 6 volts are applied across it?

W=(E^2)/R

Watts = 6^2/12

Watts = 36/12 = 3.

To derive that power formula from ohms law:

E=I*R so I=E/R

W=E*I; substitute for I to get W=(E^2)/R

P=U.I

and I=U/R

so P=U²/R

so P=36/12

P=3 Watt

You will need ohm's law to calculate that answer.

I = E/R and P= EI

1. You know that E is 6V and R is 12 Ω.

2.. First, calculate I (Current)

3. Then you can calculate P (Power) from E * I

Good luck

haha.

Same course as me, how much dissipation will be afflicted on a 12 core wire when you put 10 volts through it?

Who gives a ****!!

btw, i=v/r so 6 divided by 12 equals your answer.

but, who gives a ****

3 watts

power=work done/time taken

power= vit/t

power=vi

since you have been given resistance and voltage,

remember i=v/r

so now

power=(v*v)/r

power=(6*6)/12

power=36/12

power=3 watts

0.5 amperes