how do you convert an int to a string in c++?

conversion of an int to a string in c++, using a stringstream object :

method 1:

#include <iostream>

#include <sstream> // Required for stringstreams

#include <string>

std::string IntToString ( int number )

{

std::ostringstream oss;

// Works just like cout

oss<< number;

// Return the underlying string

return oss.str();

}

int main()

{

int number = 12345;

std::string result = IntToString ( number );

// Now we can use concatenation on the number!

std::cout<<"~~{" + result + "}~~\n";

}

method 2 : it will display as true r false

#include <sstream>

#include <string>

using namespace std;

bool StringToInt(const string &s, int &i);

int main(void)

{

string s1 = "12";

string s2 = "ZZZ";

int result;

if (StringToInt(s1, result))

{

cout << "The string value is " << s1

<< " and the int value is " << result << endl;

}

else

{

cout << "Number conversion failed" <<endl;

}

if (StringToInt(s2, result))

{

cout << "The string value is " << s2

<< " and the int value is " << result << endl;

}

else

{

cout << "Number conversion failed on " <<s2 <<endl;

}

return(0);

}

bool StringToInt(const string &s, int &i)

{

istringstream myStream(s);

if (myStream>>i)

return true;

else

return false;

/*

* Program output:

The string value is 12 and the int value is 12

Number conversion failed on ZZZ

*

*/

method 3 : The simpest method of all

#include<iostream>

#include<string>

#include<sstream>

using namespace std;

string itos(int i)// convert int to string

{

stringstream s;

s << i;

return s.str();

}

int main()

{

int i = 127;

string ss = itos(i);

const char* p = ss.c_str();

cout << ss << " " << p << "\n";

}

#include<stdlib.h>

...

for integer

itoa(int n,char* s);

for long

ltoa(long int n, char*s);