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The drag force on large objects such as cars, planes, and sky divers moving through the air is Fd=-bv^2?
The drag force on large objects such as cars, planes, and sky divers moving through the air is Fd=-bv^2
a) for this quadratic dependence on v, determine a fromula for the terminal velocity (vt)
b) A 75kg sky diver has a terminal velocity of about 60m/s; determine the value of the constant b.
2. a 28kg block is connected ot an empty 1kg bucket by a cord running over a frictionless pulley. the coefficient of static friction between the table and the block of .450 and the coefficient of kinetic friction between the table and the block is .320 sand is gradually added to the bucket until the system just begins to move
a) calculate the mass of sand added to the bucket.
b) calculate the acceleration of the system
show all work
2 Answers
- Anonymous1 decade agoFavorite Answer
1
A) mg=bv^2 so v= sqrt(mg/b)
B) b=mg/v^2=75*9.81/60^2=0.204
2
A) To move the block requires a force of:
mg*Cstatic=28*9.81*.450=123.6N
Divide by G to get 12.6 Kg
Subtract the wight of the bucket to get 11.6kg of sand needed.
B)The system is pulled by a force of 123.6N
the system is retarded by friction of mg*Cinetic=28*9.81*.320=87.9N
thus the total accelerating force is 123.6-87.9=35.7N
The total system mass is block+bucket+sand=28+1+11.6=40.6kg
As per F=ma, a=F/m so 35.7/40.6
accel=0.87m/s^2
- ?Lv 44 years ago
[ ] Their velocity will shrink [X] Their acceleration will develop into 0 [ ] they are going to stop in mid air [ ] Their velocity will boost [X ] they are going to preserve consistent velocity from then on [ ] they are going to nonetheless accelerate, yet at below "g" [X ] they are going to now no longer accelerate see you later because the upward stress from the air drag continues to be consistent and balances out the 500N weight of the skydiver (112lb skydiver plus kit looks somewhat low...) then a uniform "terminal velocity" will result. As continuously, even as forces are *balanced*, uniform action consequences. even as forces are *unbalanced*, the equipment will accelerate contained in the route of the more suitable stress.
