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Find the area of an elipse with the given parametric equation.?
This seems to be an easy problem but everything i try is wrong...... the given equations are x=9cos@ and y=21sin@ where @ +theta. How do i find the area of the elipse thanks.
2 Answers
- morningfoxnorthLv 61 decade agoFavorite Answer
The area of an ellipse is = pi * A * B, where A is the major axis and B is the minor axis.
In your problem, A = 21 and B = 9, so the area is = 3.14159 * 21 * 9
- 4 years ago
x = 25ae273b2b51da36f51cf2af266f42a6d (one million+t^4) ... (one million) y = 2t^3 5ae273b2b51da36f51cf2af266f42a6d5ae273b2... t^4) ... (2) Squarring and jointly with eqns. (one million) and (2), x² + y² = 4t² 5ae273b2b51da36f51cf2af266f42a6d5ae273b2... t^4)² 5ae273b2b51da36f51cf2af266f42a6dt^6 5ae273b2b51da36f51cf2af266f42a6d5ae273b2... t^4)² = 4t² (2t / (one million + t^4) ] * [ 2t^3 / (one million + t^4) t^45ae273b2b51da36f51cf2af266f42a6d (2t / (one million + t^4) ] * [ 2t^3 / (one million + t^4) t^4)² = 4t² 5ae273b2b51da36f51cf2af266f42a6d5ae273b2... t^4) => (x² + y²)² = 16t^2t / (one million + t^4) ] * [ 2t^3 / (one million + t^4) (2t / (one million + t^4) ] * [ 2t^3 / (one million + t^4) t^4)² = 4 * [25ae273b2b51da36f51cf2af266f42a6d (2t / (one million + t^4) ] * [ 2t^3 / (one million + t^4) t^4) ] * [ 2t^3 5ae273b2b51da36f51cf2af266f42a6d5ae273b2... t^4) ] = 4xy
