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kim
Lv 4
kim asked in Education & ReferenceHomework Help · 1 decade ago

Math Homework?

The teacher allows the class to have a pizza party. The delivery pizza shop runs a special such that gives 1st large pizza in an order costs $15.99, the 2nd pizza (in the same order) costs half the price of the 1st, the 3rd pizza costs half the price of the 2nd, the 4th costs half the price of the 3rd, as so on. If you can only buy whole pizzas and your class has exactly $31.75 to spend on pizza (excluding tax and tip), what is the greatest number of pizzas your class can get?

Solutions please....♥

Update:

Solutions :)

3 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    1st pizza: $15.99

    2nd pizza -half of first: $15.99/2

    3rd pizza -half of second: $15.99/4

    4th pizza - half of third: $15.99/8

    notice that the numerator is always $15.99 and the denominator for each is a power of 2.

    ..................

    so the Nth pizza will cost: $15.99/[2 to the (N-1) power]

    ***why is is 2^ (N-1) power? Just look at the first 4 terms above..for the 2nd pizza the denominator is 2^1; for the 3rd pizza the deniminator is 2^2; for the 4th pizza the denominator is 2^3...always one behind!

    31.75 = 15.99 + 15.99/2...+15.99/(2^(n-1))

    31.75 = 15.99 (1 + 1/2 +....+1/(2^(n-1)) )

    n=7

    OR, very simple...

    Total =31.75 so just keep adding prices until u get to the 31.75

    1st pizza - approx $16

    2nd pizza -approx $8

    3rd pizza -approx $4

    4th pizza-approx $2

    5th pizza-approx $1

    6th pizza-approx $.50

    7th pizza-approx $.25

  • 1 decade ago

    first, just round the 15.99 to 16. So the first pizza costs $16, ($16) so the second costs $8, ($24) so the third costs $4, ($28) so the fourth costs $2, ($30) so the fifth costs $1, ($31), so the sixth costs $.5, ($31.50), so the seventh costs $.25 ($31.75). So it's around 7 it think.

  • 1 decade ago

    Seven pizzas (cost $31.74)

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