Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Edward
Lv 7
Edward asked in Science & MathematicsPhysics · 1 decade ago

A solid disk of 10 kg ..?

Yes! A solid disk of 10 kg and a radius R=1m, 12.5 cm wide starts rolling down a 10 degree incline when it is 1 m above the base of the incline. Assuming no slippage compute:

(a) Translational velocity when it gets to the bottom of the incline?

(b) It’s potential energy?

(c) It’s total energy?

(d) How old is the observer?

1 Answer

Relevance
  • Anonymous
    1 decade ago
    Favorite Answer

    CONSERVATION OF ENERGY

    initial PE = mgh

    =

    final KE (translational and rotational)

    = 1/2mv^2 + 1/2 I (omega)^2

    omega is just v*r

    Your book should have a table that tells you the moment of inertia of the disk in terms of m and r.

    So they give you m. You know g. They give you h. You can express I and omega in terms of m,r, and v. I don't see that the width of the disk is relevant.

    The only thing you don't know in that equation is v. Solve for it.

    PE = mgh at the top

    That is also the total energy--it's all you had up at the top.

    The observer is ancient.

Still have questions? Get your answers by asking now.