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never_cry_for_nothing
never_cry_for_nothing asked in Science & MathematicsMathematics · 1 decade ago

can anybody tell me??? how this become that?

{k2(k1/k3)^1/2 }/k1+k1= k2/2(k1k3)^1/2

4 Answers

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  • Mathematica
    Lv 7
    1 decade ago
    Favorite Answer

    {k2(k1/k3)^1/2 }/k1+k1= k2/2(k1k3)^1/2

    I'm going to change this to different variables to make it easier to read.

    k1 = a

    k2 = b

    k3 = c

    {b(a/c)^1/2 }/a+a= b/2(ac)^1/2

    So, taking the left side:

    b(a/c)^(1/2) / (a + a)

    = b(a/c)^(1/2) / 2a

    = b(a)^(1/2) (1/c)c^(1/2) / 2a

    = b / 2c^(1/2)a^(1/2)

    voila!

  • sweet n simple
    Lv 5
    1 decade ago

    {k2(k1/k3)^1/2 } /k1+k1

    [k2 x k1^1/2 x k3^-1/2 ] /2k1

    k2 x k1^1/2 x k3^-1/2 x 1/2 k1^-1

    [k2 k1^-1/2 k3^-1/2] /2

    k2/ [2(k1k3)^1/2]

  • Anonymous
    1 decade ago

    it is simply a eqation of pie and algebra

  • Anonymous
    1 decade ago

    any one tell him i need to know

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