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Sarang
Sarang asked in Science & MathematicsChemistry · 1 decade ago

Please solve: A partially dry sample contained 50% of silica and 7% of water. The original clay contained ....

12% of water. Find the percentage of silica in the original sample.

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  • Anonymous
    1 decade ago
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    The partially dried sample contains 50 g of silica, 7 g of water and 43 g of other materials per 100 g of sample.

    If the sample only lost x g of water then

    (7 + x) / (100 + x) = 12 / 100 or x = 5.7 g

    Thus silica = 100 x 50 /(100 + 5.7) = 47.3 %

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