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What is the magnitude of the acceleration??
An object moving in the xy-plane has coordinates that vary with time according to:
x= 2t + t squared >> only the second "t" is squared
y= 1 - 0.5t cubed >> only the "t" is cubed
The componant of the acceleration vector alone the direction of the velocity vector at t=2 sec. has a magnitude of how much??
As Soon As POSSIBLE :)
3 Answers
- 1 decade agoFavorite Answer
as u know
vx(velosity in the x axis)=d(x)
vy(velosity in the y axis)=d(y)
and
ax(acceleration in the x axis)=d(vx)
ay(acceleration in the y axis)=d(vy)
so
vx=2+2t and ax=2 and ax in t=2 is 2
vy=3/2(t^2) and ay=3t and ay in t=2 is 3*2=6
and |a|= sqr(2^2+6^2)=sqr(40)
- 1 decade ago
The first derivative will tell you the velocity, and the second derivative will give you the acceleration function.
- 1 decade ago
See if any of these websites help
Source(s): http://ca.answers.yahoo.com/question/index?qid=200... http://www.answers.com/topic/acceleration?cat=biz-... http://cnx.org/content/m13769/latest/ http://abyss.uoregon.edu/~js/glossary/acceleration...