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Explain then answer if you can?
What is the inverse LaPlace Transform of 7[e^(-7s)]/(s+7) I suspect it is the result of two functions one of whom is right time shifted by 7 sec.
2 Answers
- Anonymous1 decade agoFavorite Answer
sorry
no idea
- genericman1998Lv 51 decade ago
The 1/(s+7) factor is the transform of e^(-7t). Let's consider that our starting point.
Next, as you suspect, the factor e^(-7s) means the time-function is right-shifted by 7 units, so instead of
e^(-7t)
it's
e^(-7[t-7]) x u(t-7)
where u(t-7) is the unit step function.
Finally, there's the overall factor of 7, so multiply the time-function by 7 as well.
Hope this helps.
Source(s): see #2.9 at http://www.vibrationdata.com/Laplace.htm and the "Time Shift" transform at http://www.swarthmore.edu/NatSci/echeeve1/Ref/LPSA...
