Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Multivariable Calc. problem. How would you use the Green's Theorem to evaluate the line integral below...?
Using the Green's Theorem to evaluate the line integral
∫ P(x, y) dx+ Q(x, y) dy
C
where C is the path from (0, 0) to (1, 0) along y = 0; then from (1, 0) to (1, 1) along x = 1; then from (1, 1) to (0, 0) along y = x^1/2, given that P(x, y) = y^8, and Q(x, y) = 6xy.
This are the possible answers in the back of the book....
a. 1
b. 11/10
c. 7/6
d. 17/14
e. 5/4
f. 23/18
g. 13/10
h. 29/22
i. 4/3
or is it none of these?
3 Answers
- mathematicianLv 71 decade agoFavorite Answer
Well, dQ/dx=6y and dP/dy=8y^7, so Green's theorem says that the integral is the same as the double integral over the region contained of
6y-8y^7
The limits of the double integral will be 0 to 1 for x and 0 to x^1/2 for y. The inside integral will give 3y^2-y^8 evaluated from 0 to x^1/2, so
3x-x^4.
This is then integrated from 0 to 1 to give (3/2)x^2-(1/5)x^5 from 0 to 1, or
3/2-1/5=13/10.
- сhееsеr1Lv 71 decade ago
Well, let's take a look at the theorem:
http://en.wikipedia.org/wiki/Greene%27s_theorem
This means we want to compute:
â Q / âx = 6y
â P / ây = 8y^7
â Q / âx - â P / ây = 6x
So we're simply looking at:
â«â« (6y - 8y^7) dydx
over the unit square between the origin and (1,1).
We get:
1 1
â«â« (6y - 8y^7) dxdy
0 0
1
â« (6y - 8y^7) dy
0
3y^2 - y^8 from y=0 to y=1
3 - 1 = 2