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Olivia
Lv 4
Olivia asked in Science & MathematicsMathematics · 1 decade ago

Multivariable Calc. problem. How would you use the Green's Theorem to evaluate the line integral below...?

Using the Green's Theorem to evaluate the line integral

∫ P(x, y) dx+ Q(x, y) dy

C

where C is the path from (0, 0) to (1, 0) along y = 0; then from (1, 0) to (1, 1) along x = 1; then from (1, 1) to (0, 0) along y = x^1/2, given that P(x, y) = y^8, and Q(x, y) = 6xy.

This are the possible answers in the back of the book....

a. 1

b. 11/10

c. 7/6

d. 17/14

e. 5/4

f. 23/18

g. 13/10

h. 29/22

i. 4/3

or is it none of these?

3 Answers

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  • 1 decade ago
    Favorite Answer

    Well, dQ/dx=6y and dP/dy=8y^7, so Green's theorem says that the integral is the same as the double integral over the region contained of

    6y-8y^7

    The limits of the double integral will be 0 to 1 for x and 0 to x^1/2 for y. The inside integral will give 3y^2-y^8 evaluated from 0 to x^1/2, so

    3x-x^4.

    This is then integrated from 0 to 1 to give (3/2)x^2-(1/5)x^5 from 0 to 1, or

    3/2-1/5=13/10.

  • 1 decade ago

    Well, let's take a look at the theorem:

    http://en.wikipedia.org/wiki/Greene%27s_theorem

    This means we want to compute:

    ∂ Q / ∂x = 6y

    ∂ P / ∂y = 8y^7

    ∂ Q / ∂x - ∂ P / ∂y = 6x

    So we're simply looking at:

    ∫∫ (6y - 8y^7) dydx

    over the unit square between the origin and (1,1).

    We get:

    1 1

    ∫∫ (6y - 8y^7) dxdy

    0 0

    1

    ∫ (6y - 8y^7) dy

    0

    3y^2 - y^8 from y=0 to y=1

    3 - 1 = 2

  • 1 decade ago

    a.

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