math question..it's easy?

Either way. Remember that the order in which you do a series of multiplications *doesn't matter*

Might find it easiest to multiply the polys first, as if you don't, you have to remember to only distribute the 2 into one or the other poly.

Multiply in the parenthesis first PEMDAS is the order of operations

2(2x+7)(2x+3)

2(4x^2+14x+6x+21)

2(4x^2+20x+21)

answer 8x^2+40x+42

distribute the 2

Do as it fits you.

Proof:

2(2x + 7) (2x + 3)

(4x + 14) (2x + 3)

8x^2 + 40x + 42

2([2x + 7] [2x + 3])

2(4x + 20x + 21)

8x^2 + 40x + 42

Either way, the results are the same.

I think it works either way. I think it's easier to distribute the polynomials in the parenthesis first! =)

Here is how to do it.....

(2)(2x+7)(2x+3)

multiply 2 with both 2x+7 and 2x+3

so u get, (4x+14)(4x+6)

= 4x(4x+16)+14(4x+6)

= 16x^2 + 64x + 56x + 84

= 16x^2 + 120x + 84

hope it helps!

find out what x equals.