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How would you go about solving this physics question?
Imagine a rectangular grid with the x-axis on level ground and the y-axis vertical. With distances in feet and time in seconds, an object moves from the origin according to the parametric equations
x = 1500 t,
y = -16t^2 + 144 t .
How far, in feet, from the origin will the object be when it hits the ground?
a. 9600
b. 10,800
c. 12,000
d. 13,500
e. 14,400
or none of these?
4 Answers
- 1 decade agoFavorite Answer
The answer is d) 13,500 feet
when the object hits the ground y is equal to 0
y=-16t²+144t = -16t(t-9) = 0
-16t = 0 yields t = 0 [initial condition]
t -9 = 0 yields t = 9 seconds
x = 1500t = 1500(9) = 13500 feet
- Mr PlacidLv 71 decade ago
Since the ground is the x-axis, the object will hit the ground where y=0.
-16t^2 + 144t = 0
t(-16t+144)=0
t = 0,9
Substituting, x = 1500t
x = 1500(9) = 13,500
Answer is d.
- Anonymous1 decade ago
Choice d.
y=-16t(t-9)
y=0 when t=0 or t=9.
At t=9, x=13500
