math word problem?

Let, time taken be x.

When the trains are 750 mts apart, imagine a right triangle and use Pythagoras theorem.

(750)^2 = (80x)^2 + (100x)^2

562500 = 6400 x^2 + 10000 x^2

x^2 = 562500/(16400)

x^2 = 34.298

x = 5.86

Time taken will be 5.86 hrs

This problem works out to be a geometric problem.

Using Pythagoras' Theorem:

z^2 = x^2 + y^2

if x is the train travelling west and y is the train travelling north. then we know

z^2 = (80*t)^2 + (100*t)^2

where t is the time that the trains travel.

We also know that the distance between them is 750 miles so..

750^2 = (80t)^2 + (100t)^2 = 6400t^2 + 10000t^2

16400t^2 = 750^2

=> t^2=562500/16400

Take Sqrt => t= 5.856 hours

since the trains r movin in north n west direction, they form a 90 degree angle n the final distance between is 750 miles which can be regarded as hypotenuse

80mph n 100mph r the velocity of the trains.. so their distances be 80t miles n 100t miles where t is times taken to cover tht distance..

now using pythagorean theorem:

(80t)^2+(100t)^2=750^2

6400t^2+10000t^2=562500

16400t^2=562500

t^2= 34.299

t=+- 5.856

since the time is +ve, the trains will be 750 miles apart in 5.856 hours.

the motion theh trains are perpendicular to each other

use pythagarian theorem

a^2 + b^2 = c^2

Let a and b be the distances of the trains

a = 80t

b = 100t

750^2 = (80t)^2 + (100t)^2

562500 = 16400t^2

t^2 = 34.2987

t = 5.86hrs

I could never do those. Instead of wasting brain energy I would just estimate in my head and then pick the best answer and move on. Unless you wrote it out incorrectly, this one is especially difficult since they are traveling North and West and NOT in opposite directions.

use a SYSTEM OF LINEAR EQUATIONS

]8->