math help?

is this to esay

4-4=0

ok

bec -2 sqr = +4

If a = -2 and b = 4, find b – a^2

4-(-2)^2

=0

4 - (-2^2)

=

4 - 4

=

0

I think the answer is 0. a=-2, b=4. You plug that in you get 4-(-2^2) -> 4 - 4 (A negative squared equals positive,) So the answer would be 0.

Given a = --2 and b = 4, then

b -- a^2 = 4 -- (--2)^2

= 4 -- 4

= 0

b-(a^2)

=(4)-(-2)^2

=(4)-(4) : as -2 x -2 = 4

=0

Hope this helps!

b – a^2

= (4) - (-2)^2 --------------- sub in given info ( a = -2 and b = 4 )

=4 - 4

= 0

4. its a trick question b has nothing to do with it and -2 squared is 4 because a negative times a negative equals a positive.

please tell me you are kidding?

if you can't substitute a for a and b for b to get 4-(-2)^2=4-4=0, then how are you going to do any other assignment in this class?

I am so not mathmatically inclined. but I totally respect the fact that you have that kind of mind.