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Speed of a Sinusoidal wave?
How would I find the speed of a sinusoidal wave from the following equation -
y = (0.15 m) sin(0.80x - 50t) where x is meters and t is seconds
in the form y = A sin( kx - wt)
also the mass per unit length is 12.0 g/m
there's some equation that I'm missing here.... thanks for the help
3 Answers
- Gearld GTXLv 41 decade agoFavorite Answer
The velocity of rhe displacement of the wave it's called phase velocity and it's give by:
v = w / k
Hence
v = 50/0.8 = 500/8 m/s
- vlee1225Lv 61 decade ago
This is rad from the equation as follows:
The wave equation
y = A sin ( kx - wt) can also be written as
y = A sin (k (x -ct))
where kc = w is the angular frequency in radian/sec
k is the wave number in the x- direction, the direction of propagation, and
c is the speed of the wave
so your equation is
y = (0.15 m) sin(0.80x - 50t)
k = 0.8
w = 50 = kc = 0.8c
so c = 50/0.8 = 62.5 m/s
no equation is missing. everything is there for a 1-D wave
