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Thermochemistry Problem Need Help!?
If 21.73g of Al at 398.3 (.C) is added to 151.0g of water at 20.4 (.C), what is the final temperature (.C) of the mixture?
Enthalpy Values : Specific Heat of Al (s)= 0.902 J/g-C
Specific Heat of H20 (l)= 4.184 J/g-C
Qf for H20= 6.01 kj/mol
Gv for H20= 40.67 kj/mol
1 Answer
- ChemistryMomLv 51 decade agoFavorite Answer
so the equation to use is q = mcΔT
assuming no heat loss to the environment, heat gain of water = heat loss of the Al
(21.73 g Al)(0.902 J/gºC)(398.3ºC - Tf) = (151.0 g H2O)(4.184 J/gºC)(Tf - 20.4 ºC)
solving for Tf
Tf = 31.77 ºC
