Simplified Math Equation?

1.(7n+3)5+(11+4n)2 --->distribute the 5 and 2 into the parenthesis

=(35n+15)+(22+8n) --->combine like terms

=43n+37 --->simplified expression

2. (6a+7)2+4a ---> distribute the 2 into the parenthesis

=12a+14+4a ---->combine like terms

=16a+14

hope that helped

ok, just simplify? gee thats the easy part wait till you gotta solve quadratics....and you have to put it into quadratic form :P

anyways, here we go:

(7n+3)5 + (11+4n)2

#1 Distribution:

you must distribute the 5 to the (7n+3) and the 2 to the (11+4n)

for example, (7n+3)5 = (5*7n) + (5*3) which is 35n + 15.

and (11+4n)2 which would be 8n+22.

so you end up with 35n +15 + 8n + 22. then....

#2 Simplify:

combine like terms.

e.g. 35n+8n=43n & 15+22 = 37.

so you end up with something like 43n + 37.

and thats all you have to do for just simplifying.

for the second one {(6a+7)2+4a}, you should end up with 16a+14, again just distribute the 2 into (6a+7) and combine like terms.

supposing thats all they want you to do is simplify it, thats all you gotta do. :) this is easy stuff...i like the easy stuff :D

(7n + 3)5 + (11+ 4n)2

1. Apply the Distributive Property to the 5 and 2 to get rid of the parenthesis.

35n + 15 + 22 + 8n

2. Combine your like terms and you are finished.

43n + 37

(6a + 7)2 + 4a

1. Apply the Distributive Property to the 2 to get rid of the parenthesis.

12a + 14 + 4a

2. Combine your like terms and you are finished.

16a + 14

1.(7n+3)5+(11+4n)2

(35n+15) + (22+8n)

43n+37

2. (6a+7)2+4a

12a+14+4a

16a+14

I won't give you the answers, but I will give you an example of one similar problem and work it out for you ^_^

1) (4n+7)6+(10+8n)6 --Write the original equation

>>4n+7*6+10+8n*6 --No like terms within parentesis, so remove them.

>>4n+42+10+8n*6 --P E M/D A/S: Multiplication

>>4n+42+10+52n --Multiply next set; it does not matter if there are differen variables when you multiply or divide

>>6n+52 --Combine like terms

>>6n+52 ----Final Answer---

I hope I helped :)

use distributive property

1. (7n+3)5+(11+4n)2

35n+15+22+8n

43n+37

2. (6a+7)2+4a

12a+14+4a

16a+14

( 7n+3)5+(11+4n)2

so 7 times the n. then plus 3.. then.... times 5 plus 11+4 times n then times 2

1. multiply 5 into the paranthesis and the 2 as well...then combine like terms

35n+15+22+8n

43n+37

2. multiply the 2 in the parn...and combine like terms

12a+14+4a

16a+14

1.

multiply through by 5 and 2

35n+15+22+8n

group terms

43n+37

2.

multiply through the left bit by 2

12a+14 +4a

group terms

16a+14

1) w^(7*4)=w^28 (* multiplication) 2) (a^3*a^5)^4 = (a^(3+5))^4= (a^8)^4 = a^32 3) (6^5)^7 = 6^(5*7) = 6^35 4) a^3.a^6 = a^(3+6)= a^9 5) 3x^2 * 4x^5 = 12x^(2+5) = 12x^7 6) 2m^4n^2 · 3m^3n^2 = 6m^(4+3)n^(2+2) =6m^7n^4 7) 3x^2 + x^2=4x^2 8) -5y^3 + 3y^3 - 2y^2 = -2y^3 - 2y^2 9) 7x^2y + 2xy^2 - 3x^2y = 4x^2y + 2xy^2