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statistics word problem?
Word Problem: Different cereals are randomly selected, & the sugar content (grams of sugar per grams of cereal) is obtained for each one, with the results given below for:
Cheerios: 0.03, Harmony: 0.24, Smart Start: 0.30, Cocoa Puffs: 0.47, Lucky Charms: 0.43, Corn Flakes: 0.07, Fruit Loops: 0.47, Wheaties: 0.13, Cap’n Crunch: 0.44, Frosted Flakes: 0.39, Apple Jacks: 0.48, Bran Flakes: 0.17, Special K: 0.13, Rice Krispies: 0.09, Corn Pops: 0.45, Trix: 0.43
Use a 0.05 significance level to test the claim of a cereal lobbyist that the mean for all cereals is less than 0.30g.
1 Answer
- MerlynLv 71 decade agoFavorite Answer
data <- c(0.03, 0.24, 0.30, 0.47, 0.43, 0.07, 0.47, 0.13, 0.44, 0.39, 0.48, 0.17, 0.13, 0.09, 0.45, 0.43)
One Sample t-test
t = -0.1192, df = 15, p-value = 0.4533
alternative hypothesis: true mean is less than 0.3
99 percent confidence interval:
-Inf 0.4041285
sample estimates:
mean of x
0.295
since the upper limit of the confidence interval is above 0.30 there is no evidence to support the claim. further the large p-value, another way of looking at this, says the null hypothesis, mean >= 0.30g is plausible.
