Solve the system by substitution 2x – 4y = –10 y = 4x + 6?

Substitute the phrase 4x+6 for "y":

2x-4(4x+6)= -10 (Parenthesis)

2x-16x-24= -10 (combine like terms)

-14x-24= -10 (isolate the variable by adding 24 to both sides)

-14x= 14 (divide both sides by -14)

x= -1

THEN>>>

substitue (-1) for x:

2(-1) - 4y = -10 (parenthesis)

-2 - 4y = -10 (add 2 to both sides)

-4y = -8 (divide both sides by -4)

y = 2

CHECK>>>

2(-1) - 4 (2) = -10

-2-8 = -10

-10 = -10

2x - 4y = -10

y = 4x + 6

now recombination of eqns

1st : 2x = 4y - 10

2nd : 4x = y - 6

and multiple the 2nd eqn by -4 and plus with 1st eqn for nihilate the "y"

2x = 4y - 10

-4 ( 4x ) = -4 ( y - 6 )

then

2x = 4y - 10

-16x = -4y + 24

-14x = 14

divide by -14 both sides of eqn

x = -1

use the value of "x" at 2nd eqn

y = 4( -1 ) + 6 = -4 + 6 = 2

x = -1 , y = 2 ; S = ( -1, 2 )

as a result

2x – 4y = –10

In the place of y substitute y = 4x + 6

2x – 4(4x+6) = –10

2x – 16x-24 = –10

-14 x=-10+24

-14 x=14

x=14/-14

x=-1

substitute this x value in y=4x+6

y=4x+6

y=4(-1)+6

y=-4+6

y=2

Follow my step below.

Firstly, give the first and second equation:

2x – 4y = –10y.....(1)

–10y = 4x + 6.....(2)

From (1), 2x – 4y = –10y

2x = –10y + 4y

2x = –6y

x = –3y.....(3)

Then substitute (3) into (2):

–10y = 4x + 6

–10y = 4(–3y) + 6

–10y = –12y + 6

–10y + 12y = 6

2y = 6

y = 3

Next, substitute y = 3 into (3):

x = –3(3)

x = –9

Therefore the answer must be:

x = –9 and y = 3

I hope you get the best answer for your question. Happy Halloween's Day too...

As y = 4x + 6

we substitute y in the first equation and:

2x - 4*(4x+6) = -10

2x - 16x - 24 = -10

-14 = 14x

so x = -1

As y = 4x + 6

2x - 4*(4x+6) = -10

2x - 16x - 24 = -10

-14 = 14x

x = -1

substitute 4x+6 for y in eq1

2x-4(4x+6)=-10

2x-16x-24=-10

-14x=14

x=-1

y=4(-1)+6

y=2