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Please help me...?
The length of a rectangle is 5 cm longer than the width. The perimeter is 54 cm. Find the dimensions of the rectangle...
Please include the formula that you made and the solution... I really need help... Please, answer....
And please be super specific...
2 Answers
- KathrynLv 61 decade agoFavorite Answer
The perimeter of a rectangle is the sum of the lengths of the sides. A rectangle has two length sides and two width sides. In this case, the perimeter has been given to be 54. So:
2L + 2W = 54
We know the length is 5 cm longer than the width. So:
L = W+5
Substitute W+5 for L in the first formula:
2(W+5) + 2W = 54
Distribute the 2 in the first term:
2W + 10 + 2W = 54
Combine like terms:
4W + 10 = 54
Subtract 10 from both sides:
4W = 44
Divide both sides by 4:
W = 11
The width is 11 and the length is 16
- Anonymous1 decade ago
2x + 2(x+5) = 54
2x + 2x + 10 = 54
4x = 44
x = 11
Therefore, the length is 16cm and the width is 11cm.
Hope this helps
