Please help me...?

Let the width equal "x".

Since the length is 5cm longer then the width, we can let the length equal "x+5"

Therefore:

54 = (x+5)(x)

54 = x^2 + 5x

0 = x^2 +5x -54

Use quadratic formula to solve:

x = (-b ± √(b^2 - 4ac)) / 2a

x = (-5 ± √((-5)^2 - 4(1)(-54))) / 2(1)

= (-5 ± √(25 + 216))/2

= (-5 ± √241)/2

= (-5 ± 15.5)/2

x = (-5 + 15.5)/2 OR x = (-5 - 15.5)/2

= 10.5/2 = (-20.5)/2

x = 5.25 x = -10.25

We must assume that x = 5.25 as our other value is negative.

l = x + 5

= (5.25) + 5

= 10.25

w = x

= 5.25

Therefore, the length of the rectangle is 10.25cm and the width is 5.25cm.