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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Critical Points & Max/Min?

f(x, y) = 2x^3 - 6x^2 + y^3 + 3y^2 - 48x - 45y

a) Find the critical points where the function is optimized

b) Max or Min

1 Answer

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  • 1 decade ago
    Favorite Answer

    fx(x,y) = 6x^2 - 12x -48

    setting = 0 and solving, x = 3 or -1

    fy(x,y) = 3y^2 + 6y - 45

    setting = 0 and solving, y = -5 or 3

    I believe you make all possible combinations:

    (3, -5), (3, 3), (-1, -5), (-1, 3)

    fxx(x,y) = 12x - 12 = 12(x - 1)

    fyy(x,y) = 6y + 6= 6(y + 1)

    fxy(x,y) = fyx(x,y) = 0

    Thus,

    d = fxx(x,y)fyy(x,y)- [fxy(x,y)]^2

    d = 72(x - 1) (y + 1) - 0

    for (3, -5) d <0 max

    for (3, 3) d >0 min

    for (-1, -5) d >0 min

    for (-1, 3) d < 0 max

    Hope it's right--little rusty

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