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Critical Points & Max/Min?
f(x, y) = 2x^3 - 6x^2 + y^3 + 3y^2 - 48x - 45y
a) Find the critical points where the function is optimized
b) Max or Min
1 Answer
- Linda KLv 51 decade agoFavorite Answer
fx(x,y) = 6x^2 - 12x -48
setting = 0 and solving, x = 3 or -1
fy(x,y) = 3y^2 + 6y - 45
setting = 0 and solving, y = -5 or 3
I believe you make all possible combinations:
(3, -5), (3, 3), (-1, -5), (-1, 3)
fxx(x,y) = 12x - 12 = 12(x - 1)
fyy(x,y) = 6y + 6= 6(y + 1)
fxy(x,y) = fyx(x,y) = 0
Thus,
d = fxx(x,y)fyy(x,y)- [fxy(x,y)]^2
d = 72(x - 1) (y + 1) - 0
for (3, -5) d <0 max
for (3, 3) d >0 min
for (-1, -5) d >0 min
for (-1, 3) d < 0 max
Hope it's right--little rusty