I am in algebra 1-2 and i need help with....?

You see, the equation for a line is y=mx + b

m is the slope and b is the y-intercept.

1) y-intercept is -1. idk about x-intercept

2) First, you have to find the slope. (2-5)/ (3-1)= -3/2.

Then you have to find the y-intercept. So plug in one of the points.

5=-3/2 (1) +b

5= -3/2 + b

6.5=b

The equation is y=-3/2x + 6.5

The graphical concept of x- and y-intercepts is pretty simple. The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis. The problems start when we try to deal with intercepts algebraically.

To clarify the algebraic part, think again about the axes. When you were first introduced to the Cartesian plane, you were shown the regular number line from elementary school (the x-axis), and then shown how you could draw a perpendicular number line (the y-axis) through the zero point on the first number line. So the y-axis is really the line "x = 0". In the same way, the x-axis is really the line "y = 0".

Then, algebraically,

an x-intercept is a point on the graph where y is zero, and

a y-intercept is a point on the graph where x is zero.

More specifically,

an x-intercept is a point in the equation where the y-value is zero, and

a y-intercept is a point in the equation where the x-value is zero.

1) y int. where line crosses on y axis. easier to find when x is replaced by 0

y=8(0)-1

y= -1

to find x plug in the answer for y

-1= 8x-1

+1 +1

0=8x x=0

x and y intercepts ( 0,-1)

2) find the slope of the line

m=y1-y2/x1-x2

m=5-2/1-3 = -3/2

y=mx+b

5=-3/2(1)+b

5=-3/2+b

+3/2 +3/2

b= 13/2

equation= y =-3/2x+13/2

to check the answer plug in the points

hope this helps

1. the x intercept occurs when y=0 so it is when 0-8x-1 which becomes 1=8x which means x=1/8

the y intercept occurs when x=0 so it is y=8(0)-1 which becomes y=-1

2.) to do this problem, first you have to find the slope of the line with the equation m= (y2-y1)/(x2-x1) which is equal to (5-2)/(1-3) which is equal to -3/2--this is your slope

then you plug your slope and either of your points into the equation

y-y1=m(x-x1) which become y-5=-3/2(x-1) which can be simplified to y-5=-3/2x+3/2 which can become y=-3/2x+13/2

1.) It''s actually pretty simple. Just assume the value for your y and x is ZERO

if y = 0,

y= mx + b

0 = 8x - 1

8x = 1

thus x intercept = 1/8

if x= 0

y= mx + b

y = 8(0) - 1

y intercept = 1

2.) Solve first for the slope, m

m = (y2-y1) / (x2-x1)

m = (5-2) / (1-3)

m = -3/2

equation of the line is y = mx + b

You already have m, you just need b.

To solve for b, use one of the given two points, and I use (1,5). Substitute in your equation:

y = mx + b

5 = (-3/2)(1) + b

b = 5 + 3/2

b = 13/2

The final equation is:

y = -3x/2 + 13/2

okay, so slope-intercept form is a line in the form of

y=mx+b

m is slope

b is y-intercept

Therefore, for question 1, the y-intercept is -1.

Then, to solve for the x-intercept, set y equal to zero and solve

That is,

0=8x-1

1=8x

x=1/8

Question 2:

the slope can be found by this equation:

m= (y2-y1)/(x2-x1)

= (2-5)/(3-1)

= -3/2

Then to find the y-intercept, you can use point-slope form:

y-y1= m(x-x1)

y= m(x-x1)+y1

= (-3/2) (x-1) + 5

for this step, i used 1 as x1 and 5 as y1 (as stated in the problem (1,5))

= (-3/2)x + (13/2)

At my college we took Geometry between Algebra a million and 2. i did not have any themes with that type. I nevertheless it became fairly user-friendly and exciting. there are countless teach web content and video clips you will locate on your artwork. It enables to have a chum interior a similar type or locate somebody interior the class which you would be able to pair up with and help one yet another. :)