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HaiLeY
Lv 4
HaiLeY asked in Science & MathematicsChemistry · 1 decade ago

A person accidentally swallows a drop of liquid oxygen, O2 (l), which has a density of 1.149 g/mL.?

Assuming the drop has a volume of .050mL, what volume of gas will be produced in the person's stomach at a body temperature of 98.6 degrees F and a pressure of 1.0 atm?

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    Mass O2 = 0.050 mL x 1.149 g/mL = 0.0575

    Moles O2 = 0.0575 / 32 g/mol = 0.00179

    T = 98.6 F = 37 °C = 37 + 273 =310 K

    V = nRT / p = 0.00179 x 0.0821 x 310 / 1.0 = 0.0455 L

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