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can you show me how to solve this logarithmic equation? log6 x+ log6 (x-3)=2?
thanks Kaylee, i was doing what u said but i was forgetting a step in the quad form---thanks
1 Answer
- 1 decade agoFavorite Answer
This is just like the other question I helped you with. Both log on the left of the equation have a base of 6 so you can combine two making it log6 x(x-3) =2 . Then you can B^a=p it making the problem 6^2=x(x-3). This goes to 36=x^2-3x. Then you can subtract the 36 over and factor like any ordinary factor. Although you might need the quadratic formula.
