Math Problem??!!?

This is one equation with three unknowns. you can pick any value for two of the variables, and then calculate the last variable.

You can play around with this to get whole numbers if you want. You have a solution that is a surface.

Ok, first we need to take the numerator and see how many possible ways you can add to get to 5 with three positive numbers:

5 = 1 + 2 + 2

5 = 1 + 1 + 3

Ok, now all we do is assume that x, y, and z equal 6 for the time being and put them under each number of the above equations:

5/6 = 1/6 + 2/6 + 2/6

This is a true statement, but the last two fractions can be simplified:

5/6 = 1/6 + 1/3 + 1/3

x= 6

y = 3

z = 3

Now for the second one:

5/6 = 1/6 + 1/6 + 3/6

5/6 = 1/6 + 1/6 + 1/2

x = 6

y = 6

z = 2

And that's how you do it.

x=6

y=3

z=3

Is it okay of any two are same?

If not, then pick these three 4 , 2, 12 !!

1/6+1/6+1/2=5/6

x=6

y=6

z=2

I hope i helped please pick me scince i got it first!

iDK....