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A wave function ψ =A sin (nπx/a) for the motion of a particle in a zero potential well of width ‘a’.?
Calculate the wave amplitude where ‘x’ is the position of the particle along ‘a’?.
Please tell me how to solve.
3 Answers
- kuiperbelt2003Lv 71 decade agoFavorite Answer
what you have to do is normalize this wave function
you know that the wave function tells you something about the position of the particle
the probability of finding the particle in a certain region is given by the integral of the square of the wave function, i.e.,
Integral(Ψ*Ψ dx) where the * represents the complex conjugate, but you don't have to worry about that with this function
if you try to find the probability of the wavefunction over the entire space possible, you know that you would get a probability of 1, so...
take your wavefunction, square it, integrate it and set it equal to 1, that will give you the value of A, the amplitude
in other words solve for A:
A^2Integral[Sin^2{nπx/a}dx] =1, limits of integration (0,a)
Hint: remember than n is an integer, so you should get a very simple result for your integral
- KristaLv 45 years ago
Well, if not the money, can we at least have some of their jewelry and precious metals. I want a crown made of pure gold, or whatever that thing is that popes wear on their heads.
- maussyLv 71 decade ago
you use the formula 'x' is the distance since origin;
When you use the computer do not forget that n*Pi*x/a is in radian! so when you calculate the sinus do not forget to use radians and NOT degrees!