ALGEBRA 1 area question URGENT!!!!!!!?

w = width

l = length = w + 20

If the border is 10 cm wide and the border area is 2400, then the border perimeter = 2400/10 = 240

perimeter = 2w + 2l = 2w + 2(w +20) = 4w + 40 = 240

4w = 200 w = 50, l =70

Area = w * l = 50 * 70 = 3500 cm^2

w = width of poster

w+20 = length

cardboard = 10+W+10 = W+20

cardboard length = L+20= w+20+20 = w+40

Finally boarder area =cardboard - poster = 2400

poster = w(w+20)

cardboard = (w+40)(w+20) = w^2+60w+800

w^2+60w+800-w^2-20w = 2400

40w = 1600

w = 40, l = 60, A= 2400

CB = 60 x 80 = 4800

diff = 2400 looks like it's OK

Area of poster x(x+20)

area of cardboard (x+20)( x+40) (adding 10 to each side or 20 to the length, 20 to the width)

Then, (x+20)(x+40) - x (x+20) =2400

x^2 +60x +800 -x^2 -20x = 40x +800 =2400

40x =1600

x= 40

40 (40 +20) = 40(60) = 2400

w = width of poster

w+20 = length of poster

w(w+20) = w^2 +20w = area of poster

w+20 = width of border

w+40 = length of border

(w+20)(w+40) = w^2 +60w +800 = area of border + poster

w^2+60w+800 -(w^2+20w) = 2400

40w = 1600

w = 40

Area of poster = w^2+20w = 1600 + 800 = 2400 cm^2

The areas of the poster and the border are each 2400 cm^2

l = w + 20

(w+10)(w+30) - w(w+20) = 2400

w^2 + 40w + 300 - w^2 - 20w = 2400

20w = 2100

w = 105

l = 125

area = 105 * 125 = 13125

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