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The Conservation of Mechanical Energy help1?
A 47.0 g golf ball is driven from the tee with an initial speed of 50.0 m/s and rises to a height of 26.0 m.
(a) Neglect air resistance and determine the kinetic energy of the ball at its highest point.
(b) What is its speed when it is 7.0 m below its highest point?
1 Answer
- Anonymous1 decade agoFavorite Answer
(a)
Initially the energy is all kinetic:
K = 0.047 * 50.0^2 / 2 J
At height 26.0m, the PE is:
P = 47.0 * 9.81 * 26.0 J
The KE at 26.0m is therefore:
0.047(50.0^2 / 2 - 9.81 * 26.0)
= 46.8 J.
(b)
After a fall of 7.0m, the KE is higher by:
0.047 * 9.81 * 7.0
making it
46.8 + 0.047 * 9.81 * 7.0
= 50.0 J.