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Balancing redox reactions?
I'm having trouble balancing these redox reactions. I tried them but I just can't get them to work out. Any help is much appreciated.
1) K+H2O----> KOH+H2
2) SbCl5 + KI-----> KCl + I2 + SbCl3
3) Ca(OH)2 + NaOH + ClO2 + C -----> NaClO2 + CaCO3+ H20
1 Answer
- Anonymous1 decade agoFavorite Answer
1) a( K ) + b( H2O) ----> c( KOH ) + d( H2 )
K : a - c = 0 -> a = c
O : b - c = 0 -> b = c
H : 2b - c - 2d = 0 -> a = 2d
2K + 2H2O----> 2KOH + H2
2) a( SbCl5 ) + b( KI )-----> c( KCl ) + d( I2 ) + e( SbCl3 )
Sb : a - e = 0 -> a = e
K : b - c = 0 -> b = c
I : b - 2d = 0 -> b = 2d
Cl : 5a - c - 3e = 0 -> 2a = c
SbCl5 + 2KI-----> 2KCl + I2 + SbCl3
3) a( Ca(OH)2 ) + b( NaOH ) + c( ClO2 ) + d( C ) -----> e( NaClO2 ) + f( CaCO3 ) + g( H2O )
Ca : a - f = 0 -> a = f
Na : b - e = 0 -> b = e
Cl : c - e = 0 -> c = e
C : d - f = 0 -> d = f
H : 2a + b - 2g = 0
O : 2a + b + 2c - 2e - 3f - g = 0 -> b - a - g = 0
2a + b - 2g = 0
b - a - g = 0
-> 3a - g = 0 -> 3a = g -> b = 4a
a = d = f = 1 , b = c = e = 4 , g = 3
Ca(OH)2 + 4NaOH + 4ClO2 + C -----> 4NaClO2 + CaCO3 + 3H2O