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how to solve?4P +5O2 >2P2O5 How many g of P are needed to produce 225g of P2O5?
3 Answers
- 1 decade agoFavorite Answer
225g P2O5 x (1mol P2O5 / (2x31 + 5x16)g P2O5) x (4mol P / 2mol P2O5) x (31g P / 1mol P)
Sorry I can't write this out better but that's the work..
To answer do:
(225x4x31) / ([(2x31)+(5x16)] x 2)
- Anonymous1 decade ago
In the given equation, the ratio of P to P2O5 is 4:2 or to simplify, 2:1. Given 225 grams of P205, twice that is 450 grams of P.
- steve_geo1Lv 71 decade ago
Atomic weights: P=31 O=16 P4=124 P2O5=142
The equation is already balanced.
225gP2O5 x 1molP2O5/142gP2O5 x 1molP4/2molP2O5 x 124gP4/1molP4 = 98.2g P4 to three significant figures
