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Can you help me with this math problem?
A runner leaves home and runs due east for a distance of 45 km. He returns home on the same path. If the entire trip takes 4 hours, what is his average speed.
I know how to do that problem, but I'm not sure about the next one.
The return trip of the runner in the previous question took 30 minutes longer than his trip east, although his total time was still 4 hours. What was his velocity in each direction?
How do you do this problem? Also, it would help if you give the answer, but please show me how to do it.
1 Answer
- Pi R SquaredLv 71 decade agoFavorite Answer
Hi,
A runner leaves home and runs due east for a distance of 45 km. He returns home on the same path. If the entire trip takes 4 hours, what is his average speed.
45 + 45
----------- = 22.5 km/hr <==ANSWER
.....4
The return trip of the runner in the previous question took 30 minutes longer than his trip east, although his total time was still 4 hours. What was his velocity in each direction?
x + (x+.5) = 4
2x + .5 = 4
2x = 3.5
x = 1.75
He spent 1.75 hours going east and 1.75 + .5 or 2.25 hours heading back west.
Since he went 45 km each way, going east his velocity was 45 km/1.75 hr = 25 5/7 km/hr. <==ANSWER
Going west he went 45 km/2.25 hr = 20 km/hr. <==ANSWER
I hope that helps!! :-)