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txaggie2514
Lv 4
txaggie2514 asked in Science & MathematicsChemistry · 1 decade ago

Given the molar solubility of Cr(OH)3 find the solubility product (Ksp)

Molar Solubility = 1.3X10^-8 M

Calculate its solubility product, Ksp.

3 Answers

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  • Johnny D
    Lv 7
    1 decade ago
    Favorite Answer

    Cr(OH)3(s)====>Cr^3+(aq) + 3OH-(aq)

    Ksp=[Cr^3+][OH-]³

    =[1.3x10^-8][3x1.3x10^-8]³

    =7.7x10^-31

  • Anonymous
    5 years ago

    Why do you want the answer, and not the way to get to it? Get this in your head and you won't have difficulties with this kind of problem again: Write down the definition of Ksp Use molar concentration as your unknown x As Dr. A explains, this gives you 4x^3 = Ksp So x = cuberoot(Ksp/4) Do your own arithmetic, notice how the problem was solved, and learn something!

  • skipper
    Lv 7
    1 decade ago

    Ksp = [Cr+3][OH-]^3

    [Cr+3] = 1.3x10^-8

    [OH-] = 3x(1.3x10^-8)

    Ksp = 7.7x10^-31

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