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How many atoms of nitrogen are in a 3.7 gram sample of aspartame?
Nitrogen is 14.01 g/mol
Aspartame = C14 H18 N2 O5 (294.304 g/mol)
3 Answers
- DennisLv 51 decade agoFavorite Answer
Get the grams of asparteme into moles. When you have how many moles of aspartame, multiply it by two, since there's two moles of N in one mole of asparteme. Then convert the moles of N into atoms, by mutiplying the moles of N with avogadro's number.
- ?Lv 45 years ago
If it includes three.34x10^23 molecules and there may be a million atom in keeping with molecule, then isnt it simply three.34x10^23 * a million = three.34x10^23? As for the 2d side, you'll have got to determine that out. I'm now not going again to mole town for 10 elements.
- 1 decade ago
3.7 grams of aspartame. To get moles of asp. do 3.7/294.304 which is .0125 moles. Multiply by 2 to get .250 moles times 6.02 times 10^23 (avogadros number)
This will get you atoms of nitrogen.
