using the quadratic formula how do i go about solving this one: x2 – 3x = 7x – 2?

First, get the equation in the proper quadratic equation form:

ax^2 + bx + c = 0

x^2 - 3x = 7x -2

x^2 -3x -7x + 2 = 0

x^2 -10x + 2 = 0

Then, use the quadratic formula:

x = [-b +/- √(b^2 -4ac)]/2a

Plug in the values for a, b, and c to solve for x:

a = 1

b = -10

c = 2

x = [10 +/- √((-10)^2 -4(1)(2)]/2(1)

x = [10 +/- √(100 - 8)] / 2

x = [10 +/- √92] / 2

x = [10 +/- 2√23] / 2

x = 5 +/- √23

if thats x squared then i can help you.

first you have to get all the variables on one side of the equation. you can pick either side. i would choose the left side so that x^2 can be positive.

so you have x^2 - 3x = 7x - 2

so subtract 7x from the right and left side. you now have x^2 - 3x - 7x = -2

now add 2 to both the left and right side. you now have x^2 - 3x - 7x +2 = 0.

now combine like terms (-3x and -7x = -10x) and you have x^2 - 10x +2 =0

now you have to factor this expression. however since it is not factorable you will have to use the quadratic formula

here is the formula: http://media.nasaexplores.com/lessons/01-003/image...

a,b and c are terms in the eqn x^2 - 10x +2 =0. a is the coefficient (the # in front of at the first term) since it is just x^2, this number is 1. b is the # in front of the second term, which is -10. c is 2.

now plug those #s into the quad. form. so a=1, b=-10, c=2

you get x= -(-10)+/- sqrt( (-10)^2) - 4(1)(2)

-------------------------------------------

2(1)

that becomes x= 10+/- sqrt (100 - 8)

---------------------------

2

you can divide the top and bottom by 2 to get:

x= 5+/- sqrt (100-8)

= 5 +/- sqrt (92)

= 5+/- 9.59

this means 5 + 9.59 and 5 - 9.59

x= 14.59 and -4.59

X2-3x-7x+2=0

x2-10x+2=0

ect.

x² - 3x = 7x - 2

x² - 10x + 2 = 0

For the quadratic equation ax² +bx + c = 0

the formula : the values of x are [-b (+ or - ) + √(b² - 4ac )]/2a

for this question

a =1

b= -10

c = 2

x = [-(-10) + √(10² - 4(1)( 2))] /2 and x = [-(-10) - √( 10² - 4(1)(2))]/2

x = [10 + √ 92]/2 and x = [10 - √92]/2

x = 19.6/2 and x = 0.4/2

x = 9.8 and x = 0.2

see 1st chng da equation 2 a quadratic one 4 u wont be able 2 solve it wid a quadratic form:

dat 'd be

if x2 means x raised to da power 2 then....

it goes

x2-3x-7x+2=0

x2-10x+2=0

now here u get da quadratic equation

do u noe da formula if no dan temme i'll tell it 2 ya!!!

fyn

bye

Assuming you mean x^2

Its actually quite easy

x^2 -3x -7x +2 = 0

x^2 -10x +2 = 0

Therefore x = (10 +/- (100 - 4*2*1)^1/2)/2

i.e x = 5 + (23)^1/2 or x = 5-(23)^1/2

im assuming x2 is x squared (x^2)

x^2 - 3x = 7x - 2

x^2 - 10x = -2

x^2 - 10x + 2 = 0

therefore a=1 b=-10 c=2

put the equation in standard form

x^2-10x+2=0

use the quadratic formula

x^2 - 3x = 7x - 2

x^2 - 3x - 7x + 2 = 0

x^2 - 10x + 2 = 0

x = [-b ±√(b^2 - 4ac)]/2a

a = 1

b = -10

c = 2

x = [10 ±√(100 - 8)]/2

x = [10 ±√92]/2

x ≈ [10 ±9.59]/2

x ≈ [10 + 9.59]/2

x ≈ 19.59/2

x ≈ 9.795

x ≈ [10 - 9.59]/2

x ≈ 0.41/2

x ≈ 0.205

∴ x ≈ 0.205 , 9.795

your answer would be 2x- 3x-7x=-8x/-2=4

your answer is 4