(-1/3)(6/5)(-10)= 4 Can someone show how this is done.?

(-1/3)(6/5)(-10)=

multiply the numerators (top number of a fraction or numbers which are not written as fractions)

-1 * 6 * -10 = 60

multiply the denominators (bottom number of a fraction)

3 * 5 = 15

then divide these two numbers

60/15 = 4

For your second problem

(-1/2)(6/3)(9)

start the same way

Multiply numerators

-1 * 6 * 9 = -54

Multiply denominators

2 * 3 = 6

divide them

-54/6 = -9

then to get the reciprocal you flip a fraction upside down or when they aren't fractions you put the number into the denominator of a fraction

reciprocal of -9 is -1/9

-1/3 6/5 -10/1= 3 becomes a -1 ; 6 is a 2 and the 5 is 1 and -10 is now -2

-1*2/1*-2/1=4

-1/2 6/3 9/1= 2 becomes -1; 6 becomes 3; 3 becomes 1 and 9 is 3

-1(2)(3)=-6 its reciprocal is -1/6

have you ever heard of PEMDAS? it's a pattern for solving those weirder patterned equations. it goes Parenthesis Exponent Multiply Divide Add Subtract. if there is a number joined to a parenthesis it means to multiply it, like so. 4(2)=8. so, the problem translates to -1/3 X 6/5 X -10 = 4. and that reciprocal thing? reciprocals need you to flip the two numbers in the fraction, but with equations you could either flip the answer or each of the numbers in the equation. so, it would be (-2)(3/6)(1/9) [the answer is -1/9]

multiply the numerator (-1)(6)(-10) = 60

multiply the denominator (3)(5)=15

divide so u get 60/15=4

-1/3 * 6/5 = -6/15

-6/15 * -10 = 60/15

60/15 = 4

1)

(-1/3)(6/5)(-10)

= [(-1 * 6)/(3 * -5)][-10]

= (-6/15)(-10)

= 60/15

= 4

2)

(-1/2)(6/3)(9)

= (-6/6)(9)

= (-1)(9)

= -9

The reciprocal of (-1/2)(6/3)(9) is:

-1/9

(-1) (6) (-10)

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(3) (5)

(6) (10)

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(3) (5)

4