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Instantaneous Velocity with derivative help please!!?
A electron moving along the x axis has a position given by x = 14t e^(-1.3t) m, where t is in seconds. How far is the electron from the origin when it momentarily stops?
i know i have to use the product rule...now im lost...please help
3 Answers
- Engineer-PoetLv 71 decade agoFavorite Answer
Here's what you're looking for:
d(ab) = a db + b da
a = 14t
b = e^(-1.3t)
Take the derivative, set equal to zero, solve for t; your answer is x(t).
- 1 decade ago
Addition to the answer already given, which is correct.
By taking the derivative dx/dt you obtain the speed, s at any given time. To evaluate the distance x from the origin when s =0 you obtain the solution proposed.
- Anonymous5 years ago
Instantaneous acceleration
