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Need C Programming Help: When I run this code it prints the error statement no matter what the number is.?
printf("Please enter the percentage of tax for the low bracket.\n");
scanf("%lf", &low_percent);
if(low_percent > 100 || low_percent < 0);
{
printf("Error: Your number is larger than 100 or negative.\n\n");
system("pause");
return 0;
}
For example the user could enter in "30" and the program would still say "Error: Your number is larger than 100 or negative." What am I doing wrong?
I printed out the variable before the If statement and it's the same as what I entered. I then tried adding 5 to the variable before the If statement and it came out to what you'd expect, the original variable I entered, plus 5. Any other ideas? I think it's a problem with my if statment since scanf seems to be working fine.
Changing it to float didn't do anything. I decided to add the ".0" after the numbers in my If statement, but that didn't work either.
Ah ha! You had it #2. It was the semi-colon after the condition lol. Many thanks.
3 Answers
- Anonymous1 decade agoFavorite Answer
try this corection
make sure the low_percent is declared float
use %f as format specifier
and remove the semicolon after your condition
float low_percent;
scanf("%f", &low_percent);
if(low_percent > 100.0 || low_percent < 0.0)
- GirlLv 51 decade ago
Your scanf may not br formatted properly. In that case, output what low_percent is before the if statement.
Otherwise, I'd think your low_percent is not an integer. Check its type by doing something that is restricted to numbers, like temp = low_percent + 5. If it is a non-number type, this should raise an exception.
For example, in Python:
>>> "30" > 100
True
- Tizio 008Lv 71 decade ago
3 .... was writing an answer before reading all the details... while writing the answer eyes fell on the last lines about #2 ... o yes. thumbing up #2 ... but still writing an answer ... :D
