Please explain how to solve: 1-3/4(x-3)=2?

okay first, distribute your fraction

1-(3/4 times x)-(3/4 times -3 ) = 2

1 - 3x/4 + 9/4 = 2

(negative times a negative is a positive)

Mutiply the whole equation by 4 to get rid of the fractions

4(1 - 3x/4 + 9/4 = 2)

4 - 3x + 9 = 8

(the 4 cancelled out the demonimator (bottom fraction number))

add 3x

4 + 9 = 8 +3x

Simplify

13 = 8 +3x

subtract 8

5 = 3x

divide by 3

5/3 = x

Well first you distribute the -3/4 to the numbers in parenthesis.

for example you mulitply the -3/4 to the x and the -3 and then you end up with 1-3/4x+3/2=2.

Then add like terms (terms are numbers with no variable, like x or y, or any squares on the variables like x^2, x^3, etc.). So you take 1-3/2.

So you end up with 5/2-3/4x=2.

Then you subtrace the 5/2 to the other side of the equation. and you end up with -3/4x= -1/2.

Then you divide by -3/4 on both sides, it cancels on the x side and you end up with 1/24

Understand? If not feel free to email me.

1-3/4(x-3)=2 subtract 1 from both sides

-3/4(x-3)=2 multiply by -4/3

x-3=-8/3 add 3

x= -8/3+9/3

x=1/3

1 - 3/4x + 9/4 = 2

-3/4x = 2 - 1 - 9/4

-3/4x = 8/4 - 4/4 - 9/4

-3/4x = -5/4

x = -5/4 divided by -3/4

= -20/-12

= 5/3

:)

1-3/4(x-3)=2

+3/4

1(x-3)=2 and 3/4

-1

(x-3)=1and 3/4

+3

x=4 and 3/4

You have to cancel everything out, and switch it over to teh other side until x is the only thing left on one side, andthats your answer>

HAHAHA! We all suck at math!

ask your teacher!