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Collision physics question?
A cart with mass 400. g has a velocity of 0.90 m/s in the positive x direction. If this cart collides with a second stationary cart of mass 250 g. What is the velocity of the two carts after the collision if they stick together upon impact?
How much kinetic energy is lost in the collision?
2 Answers
- 1 decade agoFavorite Answer
Pi=Pf
m1v1+m2v2=(m1+m2)u where v: velocity before collision and u: velocity after collision.
0.4*0.9+0.25*0=0.65*u u=0.55 m/s
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Ei=1/2*m1*v1^2=1/2*0.4*(0.9^2)=0.162J
Ef=1/2*(m1+m2)*u^2=1/2*0.65*0.55^2=0.098J
Lost energy is the difference =0.064J
- 1 decade ago
This is a basic momentum question just a simple plug and chug if you have the equations. p(in)=p(out)
