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How many moles of Al2(SO4)3 would be produced if 6 mol of H2SO4 reacted with an excess of Al2O3.?
Al2O3 (s) + 3H2SO4 (aq) > Al2(SO4)3(aq) + 3H2O(l)
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- 1 decade agoFavorite Answer
when you have 3 moles of H2SO4 it'll produce 1 mole AL2(SO4)3 when reacted with 1 mole AL2O3 now that you have 6 moles of H2SO4 it'll be like this:
6molH2So4 x 1molAl2(SO4)3 / 3molH2SO4 = 2molAL2(SO4)3
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