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How many moles of Al2(SO4)3 would be produced if 6 mol of H2SO4 reacted with an excess of Al2O3.?

Al2O3 (s) + 3H2SO4 (aq) > Al2(SO4)3(aq) + 3H2O(l)

2 Answers

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  • 1 decade ago
    Favorite Answer

    when you have 3 moles of H2SO4 it'll produce 1 mole AL2(SO4)3 when reacted with 1 mole AL2O3 now that you have 6 moles of H2SO4 it'll be like this:

    6molH2So4 x 1molAl2(SO4)3 / 3molH2SO4 = 2molAL2(SO4)3

  • Dr.A
    Lv 7
    1 decade ago

    The ratio between H2SO4 and Al2(SO4)3 is 3 : 1

    moles Al2SSO4)3 = 6 x 1 / 3 = 2

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