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How many moles of Al2O3 are required to make 2 mol H2O?
and If 588.0 mol of Al2O3 react with excess H2SO4, how many moles of each of the products would be produced ?
Al2O3 (s) + 3H2SO4 (aq) > Al2(SO4)3(aq) + 3H2O(l)
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- Anonymous1 decade agoFavorite Answer
588.0 mol Al2(SO4)3(aq)
1764 mol H2O(l)
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